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%平面波展開法
%二維聲子晶體帶結(jié)構(gòu)計(jì)算
%計(jì)算二維正方格子
%散射體立于基體之中
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clear;clc;tic;epssys=1.0e-6;?%設(shè)定一個(gè)最小量，避免系統(tǒng)截?cái)嗾`差或除零錯(cuò)誤
?
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%定義實(shí)際的正空間格子基矢
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a=0.02;
a1=a*[1?0];
a2=a*[0?1];
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%定義晶格的參數(shù)
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rho1=11600;E1=4.08e10;mju1=1.49e10;lambda1=mju1*（E1-2*mju1）/（3*mju1-E1）;?%散射體的材料參數(shù)
rho2=1300;E2=1.175e5;mju2=4e4;lambda2=mju2*（E2-2*mju2）/（3*mju2-E2）;?%基體的材料參數(shù)
Rc=0.006;?%散射體截面半徑
Ac=pi*（Rc）^2;?%散射體截面面積
Au=a^2;?%二維格子原胞面積
Pf=Ac/Au;?%填充率
?
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%生成倒格基矢
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b1=2*pi/a*[1?0];
b2=2*pi/a*[0?1];
?
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%選定參與運(yùn)算的倒空間格矢量，即參與運(yùn)算的平面波數(shù)量
%設(shè)定一個(gè)lm的取值范圍，變化lm即可得出參與運(yùn)算的平面波集合
NrSquare=10;?%選定倒空間的尺度，即lm（倒格矢G=l*b1+m*b2）的取值范圍。
?????????????%NrSquare確定后，使用Bloch波數(shù)目可能為（2*NrSquare+1）^2
G=zeros（（2*NrSquare+1）^22）;?%初始化可能使用的倒格矢矩陣
i=1;
for?l=-NrSquare:NrSquare
????for?m=-NrSquare:NrSquare
????????G（i:）=l*b1+m*b2;
????????i=i+1;
????end;
end;
NG=i-1;?%實(shí)際使用的Bloch波數(shù)目
G=G（1:NG:）;?
?
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%生成k空間的rho（Gi-Gj）mju（Gi-Gj）lambda（Gi-Gj）值，ij從1到NG。
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rho=zeros（NGNG）;mju=zeros（NGNG）;lambda=zeros（NGNG）;
for?i=1:NG
????for?j=1:NG
????????Gij=norm（G（j:）-G（i:））;
????????if?（Gij????????????rho（ij）=rho1*Pf+rho2*（1-Pf）;
????????????mju（ij）=mju1*Pf+mju2*（1-Pf）;
????????????lambda（ij）=lambda1*Pf+lambda2*（1-Pf）;
????????else
????????????rho（ij）=（rho1-rho2）*2*Pf*besselj（1Gij*Rc）/（Gij*Rc）;
????????????mju（ij）=（mju1-mju2）*2*Pf*besselj（1Gij*Rc）/（Gij*Rc）;
????????????lambda（ij）=（lambda1-lambda2）*2*Pf*besselj（1Gij*Rc）/（Gij*Rc）;
????????end;
????end;
end;
?
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%定義簡(jiǎn)約布里淵區(qū)的各高對(duì)稱點(diǎn)
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T=（2*pi/a）*[epssys?0];
M=（2*pi/a）*[1/2?1/2];
X=（2*pi/a）*[1/2?0];
?
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%對(duì)于簡(jiǎn)約布里淵區(qū)邊界上的每個(gè)k，求解其特征頻率
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THETA_A=zeros（NGNG）;?%待解的本征方程A矩陣
THETA_B=zeros（NGNG）;?%待解的本征方程B矩陣
Nkpoints=10;?%每個(gè)方向上取的點(diǎn)數(shù)
stepsize=0:1/（Nkpoints-1）:1;?%每個(gè)方向上步長(zhǎng)
TX_eig=zeros（NkpointsNG）;?%沿TX方向的波的待解的特征頻率矩陣
XM_eig=zeros（NkpointsNG）;?%沿XM方向的波的待解的特征頻率矩陣
MT_eig=zeros（NkpointsNG）;?%沿MT方向的波的待解的特征頻率矩陣
for?n=1:Nkpoints
????fprintf（[‘\n?k-point:‘int2str（n）‘of‘int2str（Nkpoints）‘.\n‘]）;
?????
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????%對(duì)于TX（正方格子）方向上的每個(gè)k值，求解其特征頻率
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????TX_step=stepsize（n）*（X-T）+T;
?????
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????%n?求本征矩陣的元素
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????for?i=1:NG
????????for?j=1:NG
????????????kGi=TX_step+G（i:）;
????????????kGj=TX_step+G（j:）;
????????????THETA_A（ij）=mju（ij）*dot（kGikGj）;
????????????THETA_B（ij）=