資源簡(jiǎn)介
51計(jì)算器,160251計(jì)算器,160251計(jì)算器,160251計(jì)算器,160251計(jì)算器,160251計(jì)算器,1602

代碼片段和文件信息
/************************************************************************************
/ 3.?系統(tǒng)板上硬件連線? \
/ \
/ (1).?把“單片機(jī)系統(tǒng)”區(qū)域中的P0.0-P0.7與“動(dòng)態(tài)數(shù)碼顯示”區(qū)域中的 \
/ ????????ABCDEFGH端口用8芯排線連接。? \
/ \
/ (2).?把“單片機(jī)系統(tǒng)”區(qū)域中的P2.0-P2.7與“動(dòng)態(tài)數(shù)碼顯示”區(qū)域中的 \
/ S1S2S3S4S5S6S7S8端口用8芯排線連接。? \
/ \
/ (3).?把“單片機(jī)系統(tǒng)”區(qū)域中的P3.4(T0)端子用導(dǎo)線連接到“頻率產(chǎn)生器” \
/ 區(qū)域中的WAVE端子上。? \
/ \
/ 4.?程序設(shè)計(jì)內(nèi)容? \
/ \
/ (1).?定時(shí)/計(jì)數(shù)器T0和T1的工作方式設(shè)置,由圖可知,T0是工作在計(jì)數(shù)狀態(tài)下, \
/ 對(duì)輸入的頻率信號(hào)進(jìn)行計(jì)數(shù),但對(duì)工作在計(jì)數(shù)狀態(tài)下的T0, ?\
/ ????????最大計(jì)數(shù)值為fOSC/24,由于fOSC=12MHz,因此:T0的最大計(jì)數(shù)頻率為250KHz。
/ 對(duì)于頻率的概念就是在一秒只數(shù)脈沖的個(gè)數(shù),即為頻率值。 ??\
/ 所以T1工作在定時(shí)狀態(tài)下,每定時(shí)1秒中到,就停止T0的計(jì)數(shù), ???\
/ 而從T0的計(jì)數(shù)單元中讀取計(jì)數(shù)的數(shù)值,然后進(jìn)行數(shù)據(jù)處理。送到數(shù)碼管顯示出來(lái)。? \
/ ?\
/ (2).?T1工作在定時(shí)狀態(tài)下,最大定時(shí)時(shí)間為65ms,達(dá)不到1秒的定時(shí), ??\
/ 所以采用定時(shí)50ms,共定時(shí)20次,即可完成1秒的定時(shí)功能。 ???\
*********************************************************************************************************/
#include
#include
#define?uchar?unsigned?char
#define?unit?unsigned?int
#define?ulong?unsigned?long ???//(共陰)
uchar?code?dispbit[]={0xfe0xfd0xfb0xf70xef0xdf0xbf0x7f}; //?定義位選
uchar?code?dispcode[]={0x3f0x060x5b0x4f0x660x6d0x7d0x070x7f0x6f0x000x40};//定義段碼
uchar?dispbuf[8]={01234567};?//顯示緩沖
uchar?temp[8];
uchar?dispcount;
uchar?T0count;//T0計(jì)數(shù)
uchar?timecount;//時(shí)間計(jì)數(shù)
bit?flag;
ulong?x;
void?main(void)
{
TMOD=0x15;
TH0=0;
TL0=0;
TH1=(65536-4000)/256;
TL1=(65536-4000)%256;
TR1=1;
TR0=1;
ET0=1;
ET1=1;
EA=1;
while(1)
{
uchar?i;
if(flag==1)
{
flag=0;
x=T0count*65536+TH0*256+TL0;
for(i=0;i<8;i++)
{
?temp[i]=0;
}
i=0;
while(x/10)
{
temp[i]=x%10;
x=x/10;
i++;
}
temp[i]=x;
for(i=0;i<6;i++)
{
dispbuf[i]=temp[i];
}
timecount=0;
T0count=0;
TH0=0;
TL0=0;
TR0=1;
}
}
}
void?t0(void)?interrupt?1?using?1//T0工作在計(jì)數(shù)狀態(tài)下,T0的最大計(jì)數(shù)頻率為250KHz
{
????T0count++;
}
void?t1(void)?interrupt?3?using?2
{
TH1=(65536-4000)/256;
TL1=(65536-4000)%256;
timecount++;
if(timecount==250)
{
TR0=0;
timecount=0;
flag=1;
}
P0=dispcode[dispbuf[dispcount]];
P2=dispbit[dispcount];
dispcount++;
if(dispcount==8)
{
dispcount=0;
}
}?
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件???????2784??2006-12-09?13:58??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.c
?????文件???????2287??2005-08-15?14:44??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.hex
?????文件???????7805??2006-12-09?11:56??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.M51
?????文件????????702??2006-12-09?14:40??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.plg
?????文件???????1045??2006-12-09?14:40??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.Opt
?????文件???????7834??2006-12-09?11:56??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.LST
?????文件???????5943??2006-12-09?11:56??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.OBJ
?????文件?????????45??2006-12-09?11:56??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.lnp
?????文件???????2124??2006-12-08?17:42??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.Uv2
?????文件??????99582??2005-08-15?21:06??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.DSN
?????文件???????5477??2006-12-09?11:56??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer
?????文件???????1474??2006-01-07?19:32??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.SDF
?????文件???????1293??2006-01-07?19:37??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.TXT
?????文件???????1182??2006-12-09?17:09??!6位數(shù)顯頻率計(jì)數(shù)器\c\6bit_cymometer.PWI
?????文件??????99582??2005-08-15?20:55??!6位數(shù)顯頻率計(jì)數(shù)器\c\Last?Loaded?6bit_cymometer.DBK
?????目錄??????????0??2006-01-20?16:10??!6位數(shù)顯頻率計(jì)數(shù)器\sim
?????目錄??????????0??2006-01-20?16:10??!6位數(shù)顯頻率計(jì)數(shù)器\c
?????目錄??????????0??2006-01-20?16:10??!6位數(shù)顯頻率計(jì)數(shù)器
-----------?---------??----------?-----??----
???????????????239159????????????????????18
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