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    發布日期: 2024-10-09
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資源簡介

自己原創的一個讀取seg2的程序。結果生成了一個txt的文件,保存了每個道中的所有采樣點的數據。運行窗口顯示道頭字符串。程序可以運行出來,雖然還不完善,但是對大家會有很大的幫助。。好好看。讀者可以自己再繼續改。

資源截圖

代碼片段和文件信息

//?seg2讀取程序.cpp?:?Defines?the?entry?point?for?the?console?application.
//
//?讀取seg2.cpp?:?Defines?the?entry?point?for?the?console?application.
//

#include?“stdafx.h“
#include
#include
#include
#include
#include?
//#include
//#include?

?
using?namespace?std;

vector?>?tb_all?;//存儲多道數據的容器
vectortb;??????????//存儲單道數據的容器
vector?>?tb_st_all;//存儲道頭中字符串
vector?c;???????????//單個字符串中的字符
vectortp;????????????//存儲道頭(trace?pointer)指針的容器
vector::iterator?tp_iter;????//容器的指針
//map?sb?;??//存儲道頭中的字符串
//map::const_iterator?it_note?;//map的指針
?int?data[]={0};
int?jksum;
long?int?d;
char?chdata_format?;
int?block_id=0x3a55;
unsigned?short?int?n_traces?;????????//道數
unsigned?short?int?sizeof_tdb;?????//道頭的尺寸
unsigned?long?int?sizeof_db;
unsigned?short?int?n_sample;?????????//采樣點數
unsigned?short?int?shot_number;??????//炮號
double?dt?; ?????????????????????//?采樣間距?(seconds).
int?rec_location;????????????????????//檢波點位置
int?soc_location;????????????????????//炮點位置?


int?main()
{
//在文件頭讀取道數和道指針
????ifstream?infile(“e030c.dat“ios::binary|ios::in);
ofstream?ofile(“e030c.txt“ios::out);

infile.seekg(0ios_base::beg);

??infile.read(?(char*)?&block_id?sizeof(block_id)?);//讀取道頭標志
??if(block_id!=0x553A)
??????{
??cout<riptor?block?the?block?id?is?incorrect.“
???????<<“it?isn‘t?seg2?fomate“< ??}

???//??else
//?{

???infile.seekg(6ios_base::beg);
???infile.read(?(char*)?&n_traces?sizeof(n_traces)?)?;//讀取道數
????????
???//讀取道頭指針
??????infile.seekg(32ios_base::beg);
??for(unsigned?short?int?i=0;i?!=?n_traces;i++)
??{
infile.read(?(char*)?&j?sizeof(j)?);
????????????tp.push_back(j);
}

?cout<<“the?number?of?traces?is:“<
???//??infile.close();

???//----------------------------------------------------------------------------------
?//下面進入道頭塊讀取數據
????//??infile.open(“e030c.dat“ios::in);

??
?????for(i=0;i ?{

????infile.seekg(tp[i]ios_base::beg);//道頭開始位置
????????infile.seekg(2+tp[i]ios_base::beg);//道頭尺寸塊起始位置
????????infile.read((char*)?&sizeof_tdbsizeof(sizeof_tdb));//讀取道頭i+1的尺寸
????infile.read(?(char*)?&sizeof_db?sizeof(sizeof_db)?)?;//讀取數據段的長度
????????infile.seekg(8+tp[i]ios_base::beg);
????????infile.read(?(char*)?&n_sample?sizeof(n_sample)?)?;//讀取采樣點數(/道)
???????//?infile.read((char*)&data_format?sizeof(data_format)?)?;//讀取數據格式(0x01、0x02)

???????
??/*? infile.seekg(32+tp[i]ios_base::beg);
????????streampos?here?=?infile.tellg();
cout<<“trace??“< while(static_cast(here)<(sizeof_tdb+tp[i]))
{
??????????streampos?here?=?infile.tellg();
??infile.read((char?*)?&chsizeof(ch));
??cout< }
cout<?????*/


//讀取道頭中字符串
??infile.seekg(32+tp[i]ios_base::beg);

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????667??2010-04-30?09:27??seg2讀取程序\StdAfx.h

?????文件????????299??2010-04-30?09:27??seg2讀取程序\StdAfx.cpp

?????文件???????1244??2010-04-30?09:27??seg2讀取程序\ReadMe.txt

?????文件???????4610??2010-04-30?09:27??seg2讀取程序\seg2讀取程序.dsp

?????文件????????532??2010-04-30?09:27??seg2讀取程序\seg2讀取程序.dsw

?????文件??????33792??2010-04-30?09:49??seg2讀取程序\seg2讀取程序.ncb

?????文件??????82944??2010-04-30?09:48??seg2讀取程序\Debug\vc60.idb

?????文件?????187048??2010-04-30?09:28??seg2讀取程序\Debug\seg2讀取程序.pch

?????文件?????151552??2010-04-30?09:48??seg2讀取程序\Debug\vc60.pdb

?????文件???????1862??2010-04-30?09:28??seg2讀取程序\Debug\StdAfx.obj

?????文件?????589912??2010-04-30?09:48??seg2讀取程序\Debug\seg2讀取程序.exe

?????文件????1180672??2010-04-30?09:48??seg2讀取程序\Debug\seg2讀取程序.pdb

?????文件?????389168??2010-04-30?09:48??seg2讀取程序\Debug\seg2讀取程序.obj

?????文件?????847784??2010-04-30?09:48??seg2讀取程序\Debug\seg2讀取程序.ilk

?????文件??????????0??2010-04-30?09:48??seg2讀取程序\e030c.txt

?????文件?????407904??2003-03-05?10:41??seg2讀取程序\e030c.dat

?????文件???????1389??2010-04-30?09:48??seg2讀取程序\seg2讀取程序.plg

?????文件???????5110??2010-04-30?09:48??seg2讀取程序\seg2讀取程序.cpp

?????文件??????48640??2010-04-30?09:49??seg2讀取程序\seg2讀取程序.opt

?????目錄??????????0??2010-04-30?09:27??seg2讀取程序\Debug

?????目錄??????????0??2010-04-30?09:26??seg2讀取程序

-----------?---------??----------?-----??----

??????????????3935129????????????????????21


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