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資源簡介

本文介紹了單片機控制步進電機的系統。在電氣時代的今天,電動機一直在現代化的生產和生活中起著十分重要的作用。步進電機是機電控制中一種常用的執行機構, 其原理是通過對它每相線圈中的電流和順序切換來使電機作步進式旋轉。本系統的硬件組成主要有:51系列單片機、L298N驅動電路、直流電壓源等。同時對系統設計中所用到的一些軟件都進行了介紹。本系統用51系列單片機和L298N電機驅動芯片并加入了鍵盤來控制步進電機實現轉向、轉速等。系統中使用的是永磁式二相步進電機,相應的驅動和控制電路對于其整體性能起著非常重要的作用。 經系統調試,能夠很好的控制步進電機的正反轉、加減速、急停,從而達到預期目的。整個系統具有結構簡單、可靠性高、成本低和實用性強等特點,具有較高的通用性和應用推廣價值。

資源截圖

代碼片段和文件信息

#include“reg51.h“
#include“intrins.h“
#include“math.h“
#include“absacc.h“
#define??PORTA??XBYTE[0x8500]
#define??PORTB??XBYTE[0x8502]
#define??PORTC??XBYTE[0x8504]
#define??PORTC0?XBYTE[0x8506]
#define?nop?_nop_()
#define?Right_RUN??1
#define?Left_RUN??0
unsigned?long?RunSpeed=76;
unsigned??char??RUNState=1;
sbit??RS=P2^0;
sbit??RW=P2^1;
sbit??E=P2^2;
sbit?P17=P1^7;
bit???flag=0;
unsigned?char?xx[]=“speed(n/min):“;
unsigned?char?SD[]=“76“;
char??state[2][14]={“direction:cw““direction:ccw“};
unsigned?char??FLGINMA=0;
unsigned??char??ts=0x01;
unsigned??int???a;
main()
{
??void??OPJIAN();
??unsigned?char?JIAN();
??unsigned?char?JIANZHI();
???void??speed();
?void??SHOW_LCD();
?void??show_state();
?void??write1();
?void??writ2(unsigned?char?i);
?void??delay();
?void?time();
?void??busy();
?unsigned??char??i;
??i=0x90;
??PORTC0=i;
??i=0x01;
??TMOD=i;
??t=0x10;
??a=0x0f;
??TH0=0x10;
??TL0=0x0f;
??FLG=INMA;??
??SHOW_LCD();
??show_state();
??EA=1;
??ET0=1;
??TR0=1;
while(1)
{
?i=JIAN();
?????if(i!=0)
{
??time();
??time();
?}
i=JIAN();
if(i!=0)
{
INMA=JIANZHI();
???OPJIAN();
?time();
}
??if(FLG!=INMA||flag==1)
???{??FLG=INMA;
SHOW_LCD();
??????show_state();
flag=0;
}
??}
??}
?void?SHOW_LCD()/*lcd設置程序*/
?{
??P1=0x38;
??write1();
??delay();
??P1=0x38;
??write1();
??delay();?
??P1=0x38;
??write1();
??delay();
??P1=0x01;
??write1();
?delay();
??P1=0x0f;
??write1();
?delay();
??P1=0x06;
??write1();
??delay();
??P1=0x0c;
??write1();
??
?}
void??show_state()/*狀態顯示程序*/
??{
???unsigned?char?i=0;
???P1=0x80;
write1();
?while(xx[i]!=‘\0‘)
??{
????writ2(xx[i]);
?i++;
?delay();
?}
???i=0;
??while(SD[i]!=‘\0‘)
????{
??writ2(SD[i]);
??delay();
??i++;
?
??}
??P1=0xc0;
??write1();
??i=0;
??if(RUNState==Right_RUN)
?while(state[0][i]!=‘\0‘)
???{
??writ2(state[0][i]);
??i++;
?}
else
??if(RUNState==Left_RUN)
??while(state[1][i]!=‘\0‘)
???{
??writ2(state[1][i]);
???i++;
?}
???}
void??write1()/*lcd寫控制字*/
?{
???RS=0;
RW=0;
E=0;
busy();
E=1;
??}
void??writ2(?unsigned?char?i)/*lcd寫數據*/
?{?P1=i;
???RS=1;
RW=0;
E=0;
???busy();
E=1;
}
?
?void?delay()/*延時程序*/
{
??unsigned?char??i;
??for(i=0;i<100;i++)
????{
????i=i;
?}
?
}
void?time()
{?unsigned?char?ij;
for(i=0;i<100;i++)
?{?
for(j=0;j<30;j++)
?{
???j=j;
??}
??}
}

void?busy()?????????//判斷LCD是否忙
{????
?do
?{
?P1=0xff;
??RS=0;
?????RW=1;
?????E=0;
??nop;
??E=1;
??}while(P17==1);
??
?}
?unsigned?char?JIAN()/*判斷是否有鍵按下*/
?{
??unsigned?char??ij;
?????i=0xff;
?????PORTA=i;
?????time();
?????i=0x00;
?????PORTB=i;
?????j=PORTA;
?????j=~j;
?????j=j&(0x0f);
?????return??j;
?}
unsigned?char?JIANZHI()/*讀鍵值程序*/
?{
???unsigned?ijdkm=1;
?i=0xfe;
?k=0x01;
?do
?{
?PORTB=i;
?j=PORTA;
?m=j&(0x01);
????if(m==0)
???d=k/2;
?else
? ???{
?m=j&(0x02);
?????if(m

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件?????181508??2007-08-18?20:16??C語言驅動程序\步進電機.DSN

?????文件?????181508??2007-08-18?20:16??C語言驅動程序\Last?Loaded?步進電機.DBK

?????文件????????814??2007-09-19?21:54??C語言驅動程序\步進電機.PWI

?????文件????????807??2007-09-16?22:50??C語言驅動程序\d.Opt

????.......??????1658??2007-08-17?16:47??C語言驅動程序\d_Uv2.Bak

?????文件???????4103??2007-08-18?20:13??C語言驅動程序\d.c

?????文件??????????0??2007-09-16?22:02??C語言驅動程序\d.plg

?????文件??????10370??2007-08-18?20:13??C語言驅動程序\d.LST

?????文件??????15057??2007-08-18?20:13??C語言驅動程序\d.OBJ

?????文件?????????19??2007-08-18?20:13??C語言驅動程序\d.lnp

?????文件??????16616??2007-08-18?20:13??C語言驅動程序\d.M51

?????文件??????13292??2007-08-18?20:13??C語言驅動程序\d

?????文件???????3696??2007-08-18?20:13??C語言驅動程序\d.hex

????.......???????807??2007-08-18?20:14??C語言驅動程序\d_Opt.Bak

?????文件???????1662??2007-08-18?20:05??C語言驅動程序\d.Uv2

?????目錄??????????0??2007-08-16?15:02??C語言驅動程序

-----------?---------??----------?-----??----

???????????????432135????????????????????17


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