%切比雪夫插值求T（t）
Tt=[];
B=[];
for?tt=0:15:150
????tu=2*tt/150-1
????for?nn=0:135/15
????????Tt=[TtT（tunn）];
????end
????B=[B;Tt];
????Tt=[];
end
Fx=PRN1（:6）;
N=B‘*B;
U=B‘*Fx;
M=inv（N）*U;

syms?ss?sum
ss=0;
sum=0;
Xt=[];
for?jj=0:3:150
????tu=2*jj/150-1;
????for?ii=1:135/15+1
????ss=M（ii）*T（tuii-1）;
????sum=sum+ss;
????end
????Xt=[Xtsum]
????sum=0;
????ss=0;
end

?屬性????????????大小?????日期????時(shí)間???名稱
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?????文件????????298??2011-10-03?20:13??切比雪夫插值\qiebi.asv

?????文件????????400??2011-10-05?19:38??切比雪夫插值\qiebi.m

?????文件????????351??2011-10-03?17:06??切比雪夫插值\T.asv

?????文件????????370??2011-10-03?17:19??切比雪夫插值\T.m

?????目錄??????????0??2011-12-22?22:32??切比雪夫插值

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?????????????????1419????????????????????5