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    發(fā)布日期: 2021-05-10
  • 語(yǔ)言: 其他
  • 標(biāo)簽: qrs??

資源簡(jiǎn)介

上面程序獲得的數(shù)據(jù)就不便于使用了,因?yàn)槟鞘寝D(zhuǎn)換為具有實(shí)際意義的心電數(shù)據(jù),信號(hào)數(shù)據(jù)值一般在-2~2之間,單位是mV。那么,要找新的ECG讀取程序來(lái)獲取數(shù)據(jù)嗎?不用!實(shí)際上,程序rddata.m中本身就是把MIT .dat 文件中存儲(chǔ)的二值數(shù)據(jù)轉(zhuǎn)換為十進(jìn)制數(shù)據(jù),然后再進(jìn)一步處理轉(zhuǎn)換成具有實(shí)際意義的心電信號(hào)值。我們進(jìn)行信號(hào)處理時(shí),需要用到的就是從二值數(shù)據(jù)轉(zhuǎn)換來(lái)的初始十進(jìn)制數(shù)據(jù),由于 .dat文件中是三個(gè)字節(jié)存儲(chǔ)2個(gè)數(shù),即每個(gè)數(shù)12bits,轉(zhuǎn)換后得到的十進(jìn)制數(shù)范圍應(yīng)該是0~2048。我所理解的數(shù)據(jù)存儲(chǔ)方式圖示如下,不知是否正確,僅供參考:

資源截圖

代碼片段和文件信息

%本程序?qū)崿F(xiàn)基于小波變換的QRS波的檢測(cè)???%
%鄭秀玉??深圳大學(xué)德州儀器DSPs實(shí)驗(yàn)室???%
%2007年7月2日????????????????????????%

clear?all;
close?all;
points=4096;???????level=4;????sr=360;?
%讀入ECG信號(hào)
load?ecgdata.mat;
ecgdata=mydata‘;
g=importdata(‘yy.json‘);
ecgdata?=g;
plot(ecgdata(1:points));grid?on;axis?tight;axis([1points-0.0010.0015]);
title(‘ECG信號(hào)‘);

swa=zeros(4points);
swd=zeros(4points);
signal=ecgdata(0*4096+1:1*4096);

%算小波系數(shù)和尺度系數(shù)
for?i=1:points-3
??swa(1i+3)=1/4*signal(i+3-2^0*0)+3/4*signal(i+3-2^0*1)+3/4*signal(i+3-2^0*2)+1/4*signal(i+3-2^0*3);
???swd(1i+3)=-1/4*signal(i+3-2^0*0)-3/4*signal(i+3-2^0*1)+3/4*signal(i+3-2^0*2)+1/4*signal(i+3-2^0*3);
end
j=2;
while?j<=level
???for?i=1:points-24
?????swa(ji+24)=1/4*swa(j-1i+24-2^(j-1)*0)+3/4*swa(j-1i+24-2^(j-1)*1)+3/4*swa(j-1i+24-2^(j-1)*2)+1/4*swa(j-1i+24-2^(j-1)*3);
?????swd(ji+24)=-1/4*swa(j-1i+24-2^(j-1)*0)-3/4*swa(j-1i+24-2^(j-1)*1)+3/4*swa(j-1i+24-2^(j-1)*2)+1/4*swa(j-1i+24-2^(j-1)*3);
???end
???j=j+1;
end
%畫出原信號(hào)和尺度系數(shù),小波系數(shù)
figure;
subplot(level11);?plot(ecgdata(1:points));?grid?on;axis?tight;
title(‘ECG信號(hào)及其在j=1234尺度下的尺度系數(shù)及小波系數(shù)‘);
for?i=1:level
????subplot(level+122*(i)+1);
????plot(swa(i:));?axis?tight;grid?on;xlabel(‘time‘);
????ylabel(strcat(‘a(chǎn)???‘num2str(i)));
????subplot(level+122*(i)+2);
????plot(swd(i:));?axis?tight;grid?on;
????ylabel(strcat(‘d???‘num2str(i)));
end

%畫出原圖及小波系數(shù)
figure;
subplot(level11);?plot(real(ecgdata(1:points))‘b‘);?grid?on;axis?tight;
title(‘ECG信號(hào)及其在j=1234尺度下的小波系數(shù)‘);
for?i=1:level
????subplot(level+11i+1);
????plot(swd(i:)‘b‘);?axis?tight;grid?on;
????ylabel(strcat(‘d???‘num2str(i)));
end

%**************************************求正負(fù)極大值對(duì)*****************************************%
ddw=zeros(size(swd));
pddw=ddw;
nddw=ddw;
%小波系數(shù)的大于0的點(diǎn)
posw=swd.*(swd>0);
%斜率大于0
pdw=((posw(:1:points-1)-posw(:2:points))<0);
%正極大值點(diǎn)
pddw(:2:points-1)=((pdw(:1:points-2)-pdw(:2:points-1))>0);
%小波系數(shù)小于0的點(diǎn)
negw=swd.*(swd<0);
ndw=((negw(:1:points-1)-negw(:2:points))>0);
%負(fù)極大值點(diǎn)
nddw(:2:points-1)=((ndw(:1:points-2)-ndw(:2:points-1))>0);
%或運(yùn)算
ddw=pddw|nddw;
ddw(:1)=1;
ddw(:points)=1;
%求出極值點(diǎn)的值其他點(diǎn)置0
wpeak=ddw.*swd;
wpeak(:1)=wpeak(:1)+1e-10;
wpeak(:points)=wpeak(:points)+1e-10;

%畫出各尺度下極值點(diǎn)
figure;
for?i=1:level
????subplot(level1i);
????plot(wpeak(i:));?axis?tight;grid?on;
ylabel(strcat(‘j=???‘num2str(i)));
end
subplot(411);
title(‘ECG信號(hào)在j=1234尺度下的小波系數(shù)的模極大值點(diǎn)‘);

interva2=zeros(1points);
intervaqs=zeros(1points);
Mj1=wpeak(1:);
Mj4=wpeak(3:);

%畫出尺度3極值點(diǎn)
figure;
plot?(Mj4);
title(‘尺度3下小波系數(shù)的模極大值點(diǎn)‘);

posi=Mj4.*(Mj4>0);
%求正極大值的平均
thposi=(max(posi(1:round(points/4)))+max(posi(round(points/4):2*round(points/4)))+max(posi(2*round(points/4):3*round(points/4)))+max(posi(3*round(points/4):4*round(points/4))))/4;
posi=(posi>thposi/3);
nega=Mj4.*(Mj4<0);
%求負(fù)極大值的平均
thnega=(min(nega(1:round(points/4)))+min(nega(round(points/4):2*round(points/4)))+min(nega(2*round(points/4):

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件???????4558??2008-03-30?12:34??檢測(cè)QRS超級(jí)好用\100.atr

?????文件????1950000??2008-03-30?12:34??檢測(cè)QRS超級(jí)好用\100.dat

?????文件????????143??2008-03-30?12:34??檢測(cè)QRS超級(jí)好用\100.hea

?????文件???????5680??2018-03-05?17:32??檢測(cè)QRS超級(jí)好用\ecgdata.mat

?????文件???????7178??2018-03-05?16:52??檢測(cè)QRS超級(jí)好用\ecgdetect.m

?????文件???????6646??2008-03-30?12:34??檢測(cè)QRS超級(jí)好用\graduatedemo.asv

?????文件???????5470??2018-02-28?20:28??檢測(cè)QRS超級(jí)好用\rddata.m

?????文件?????165111??2018-03-05?16:25??檢測(cè)QRS超級(jí)好用\yy.json

?????目錄??????????0??2018-03-05?16:47??檢測(cè)QRS超級(jí)好用

-----------?---------??----------?-----??----

??????????????2144786????????????????????9


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