資源簡介
haar-like特征的提取代碼,效果比較好,可以直接運行
代碼片段和文件信息
%---------------------------------------------------------------------------------------------
%2?遍歷得到各點的積分
function?ii?=?bianli(I)
%I=[123456;789101112;131415161718;192021222324;252627282930;313233343536];%測試矩陣2
I=imread(‘cameraman.tif‘);
[rowcol]?=?size(I);
ii=zeros(rowcol);
for?i=1:row
for?j=1:col
?????s=sum(I(1:ij));
?????if(j-1<=0)
???????ii(ij)?=?s;
?????else
????????ii(ij)=s+ii(ij-1);
?????end
?????s=0;
???end
end
ii=buzero(ii11);
F=tezhen1(ii);
%---------------------------------------------------------------------------------------------
%3?在矩陣上面補0和左面補0
%rn?補rn行0
%cn?補cn列0
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????693??2013-11-10?21:24??haar-like\bianli.m
?????文件????????226??2013-11-10?21:19??haar-like\buzero.m
?????文件????????388??2013-11-10?21:25??haar-like\haar.m
?????文件????????635??2013-11-10?21:20??haar-like\tezhen1.m
?????目錄??????????0??2013-11-10?21:28??haar-like
-----------?---------??----------?-----??----
?????????????????1942????????????????????5
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