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資源簡介

采用多天線的認(rèn)知無線電系統(tǒng)相對(duì)于單天線認(rèn)知無線電系統(tǒng),既有傳統(tǒng)的資源(頻域,時(shí)域,碼域),又有空域資源。本文研究基于博弈論的有限反饋認(rèn)知MIMO系統(tǒng)的資源分配,涉及發(fā)射功率、空域(采用波束成形)和

資源截圖

代碼片段和文件信息

clc?;
clear?all;
Nt=4;
Iter=100;???????%迭代次數(shù)
Ith_0=1.5;??????%沒有反饋的干擾門限?1.5W
P_p=1;??????????%主用戶的發(fā)射功率1W
PT=2;???????????%認(rèn)知用戶的額定發(fā)射功率
T=1;????????????%塊衰落時(shí)間1S
Bn=0.01?????????%背景噪聲
sinr_r=0;???????%認(rèn)知用戶的信干比門限
lamti=0:0.01:1;?%波束成形變化的步長
L=length(lamti);
Nt=4;
h_1=random(‘rayleigh‘11Nt);??%認(rèn)知用戶SU1信道信息
h_2=random(‘rayleigh‘11Nt);
h_3=random(‘rayleigh‘11Nt);
h_4=random(‘rayleigh‘11Nt);
hp=random(‘rayleigh‘11Nt);???%主用戶的信道信息

h1_gain=norm(h_1);??????????????%認(rèn)知用戶SU1的信道增益
h2_gain=norm(h_2);
h3_gain=norm(h_3);
h4_gain=norm(h_4);

%%主用戶不同量化比特?cái)?shù)下,主用戶的干擾門限
%%認(rèn)知用戶在主用戶不同的反饋速率干擾溫度余量
for?n=1:1:11;???????%量化比特?cái)?shù)
????n=n-1;
Rf=n*Nt/T;??????%反饋速率
Ith_n(n+1)=P_p/(2^Rf*((Ith_0+P_p)/Ith_0)-1);?????%不同量化比特下,主用戶的干擾門限
D(n+1)=Nt/(3*4^n);???????????????????????????????%信道

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件????????7430??2020-08-26?20:44??wangchen?dalunwen\disanzhang.m
?????文件????????6616??2020-08-26?20:44??wangchen?dalunwen\disizhang.asv
?????文件????????6615??2020-08-26?20:44??wangchen?dalunwen\disizhang.m
?????文件???????10576??2020-08-26?20:44??wangchen?dalunwen\disizhang1.asv
?????文件???????17691??2020-08-26?20:44??wangchen?dalunwen\disizhang1.fig
?????文件????????9627??2020-08-26?20:44??wangchen?dalunwen\disizhang1.m
?????文件????????9773??2020-08-26?20:44??wangchen?dalunwen\disizhang2.fig
?????文件????????8883??2020-08-26?20:44??wangchen?dalunwen\disizhang3.fig
?????文件????????7346??2020-08-26?20:44??wangchen?dalunwen\diwuzhang1.asv
?????文件????????7346??2020-08-26?20:44??wangchen?dalunwen\diwuzhang1.m
?????文件??????????89??2020-08-26?20:44??wangchen?dalunwen\extremun.m
?????文件?????????191??2020-08-26?20:44??wangchen?dalunwen\feeback_rate.m
?????文件?????????128??2020-08-26?20:44??wangchen?dalunwen\rongiang_game_waterfilling.asv
?????文件?????????134??2020-08-26?20:44??wangchen?dalunwen\rongiang_game_waterfilling.m
?????文件?????????103??2020-08-26?20:44??wangchen?dalunwen\rongliang.asv
?????文件?????????103??2020-08-26?20:44??wangchen?dalunwen\rongliang.m
?????文件?????????112??2020-08-26?20:44??wangchen?dalunwen\sulvfenpei.m

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