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    文件類型: .rar
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    發(fā)布日期: 2021-02-11
  • 語言: Matlab
  • 標(biāo)簽: GPS??定位??MATLAB??GPS差分??

資源簡介

GPS單點(diǎn)定位和差分定位程序及詳細(xì)說明,始于初學(xué)者學(xué)習(xí)GPS導(dǎo)航定位原理。

資源截圖

代碼片段和文件信息

%--------------------直角轉(zhuǎn)經(jīng)緯度-------------------%
clear
clc

x=input(‘Please?input?the?parameter?(not?zero):?x?=?‘);
y=input(‘Please?input?the?parameter?(not?zero):?y?=?‘);
z=input(‘Please?input?the?parameter?(not?zero):?z?=?‘);

a=6378137;
e=1/298.257;
b=a-a*e;
e=sqrt(a*a-b*b)/a;
R=sqrt(x*x+y*y+z*z);
B=atan(z/sqrt(x*x+y*y));

%--------------------以下為迭代求fi-----------------%
fi1=acos(sqrt(x*x+y*y)/R);
buchang=0.1/60/60/180*pi;
w=sqrt(1-e*e*sin(fi1)*sin(fi1));
fi2=atan(tan(B)*(1+a*e*e/z*sin(fi1)/w));
cha=abs(fi1-fi2);
xuanze=(fi1switch?xuanze
????case?1
????????while(buchang>=0.0000001/60/60/180*pi)
????????????while(abs(fi1-fi2)<=cha)
????????????????cha=abs(fi1-fi2);
????????????????fi1=fi1+buchang;
????????????????w=sqrt(1-e*e*sin(fi1)*sin(fi1));
????????

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件???????3301??2008-12-12?09:37??test2.m

?????文件???????1950??2008-11-12?20:10??xyztojwd.m

?????文件?????252928??2008-12-14?22:38??實(shí)驗(yàn)報(bào)告.doc

?????文件?????302608??2006-11-07?21:15??GPS實(shí)驗(yàn)1\GGA.gga

?????文件????????192??2008-12-11?22:22??GPS實(shí)驗(yàn)1\GPS實(shí)驗(yàn)1要求.txt

?????文件????????219??2006-11-29?10:01??GPS實(shí)驗(yàn)2-DGPS\GPS實(shí)驗(yàn)2要求.txt

?????文件???????2111??2008-10-27?22:16??assignment1.m

?????文件????????301??2008-10-21?19:33??assignment2.m

?????文件???????3241??2008-12-04?10:20??gps_position.m

?????文件???????2761??2008-12-11?23:20??test1.m

?????目錄??????????0??2009-04-19?13:18??GPS實(shí)驗(yàn)2-DGPS\20061128-DGPS

?????目錄??????????0??2009-04-19?13:18??GPS實(shí)驗(yàn)1

?????目錄??????????0??2009-04-19?13:18??GPS實(shí)驗(yàn)2-DGPS

-----------?---------??----------?-----??----

???????????????569612????????????????????13


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