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- 語(yǔ)言: Matlab
- 標(biāo)簽: inverse??solution??逆運(yùn)動(dòng)學(xué)??matlab??
資源簡(jiǎn)介
機(jī)器人逆逆運(yùn)動(dòng)學(xué)解法學(xué)習(xí)算法,希望對(duì)大家有用。這個(gè)非常好用,謝謝
代碼片段和文件信息
%?the?input?of?program
alpha1=0;
beta1=0;
gamma1=0.5;
alpha2=0.5;
beta2=0.7;
gamma2=0;
alpha3=0;
beta3=0;
gamma3=0;
lx=100;
ly=100;
lz=0;
mx=150;
my=150;
mz=0;
nx=80;
ny=60;
nz=10;
thigh=412;
crus=385;
ankel=121.8;
center=250;
%?joint?angle?of?right?leg
%?syms?alpha1?beta1?gamma1?alpha2?beta2?gamma2?alpha3?beta3?gamma3?lx?ly?lz
%?mx?my?mz?nx?ny?nz?thigh?crus?ankel?center;
%?r11=cos(alpha1)*cos(beta1);
%?r12=cos(alpha1)*sin(beta1)*sin(gamma1)-sin(alpha1)*cos(gamma1);
%?r13=cos(alpha1)*sin(beta1)*cos(gamma1)+sin(alpha1)*sin(gamma1);
%?r21=sin(alpha1)*cos(beta1);
%?r22=sin(alpha1)*sin(beta1)*sin(gamma1)+cos(alpha1)*cos(gamma1);
%?r23=sin(alpha1)*sin(beta1)*cos(gamma1)-cos(alpha1)*sin(gamma1);
%?r31=-sin(beta1);
%?r32=cos(beta1)*sin(gamma1);
%?r33=cos(
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件???????9584??2009-12-06?15:10??invers_kinematics.m
-----------?---------??----------?-----??----
?????????????????9584????????????????????1
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