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  • 大小: 0.11M
    文件類型: .m
    金幣: 2
    下載: 0 次
    發(fā)布日期: 2023-12-28
  • 語言: Matlab
  • 標簽: 其他??

資源簡介

odefun1.m

資源截圖

代碼片段和文件信息

function??dx=odefun1(tx)
global?c2??Cn?KK2?deltav1?delta??Qdf?qk2jx?Force?Ae?Ae1?shendu
global?txl?ti
%?global?xjiasudu?yjiasudu?zjiasudu?ajiaojiasudu?bjiaojiasudu?cjiaojiasudu%(需修改)
%?global?AA??AXBO?AYBO?AZBO?alpha?beta?gamma?AXBO1?AYBO1?AZBO1?alpha1?beta1?gamma1?AXBO11?AYBO11?AZBO11?alpha11?beta11?gamma11??%(需修改)

format?long??%(將數(shù)據(jù)顯示為長整型科學計數(shù))

m0=36.28;%動平臺的質(zhì)量
%?mss=14.80;%(伸縮桿質(zhì)量矩陣中的表達)
mss=8.45;
mb=26.15;%擺動稈的質(zhì)量


lb2=0.378;%UPS擺動桿質(zhì)心到定平臺S副的距離
ls2=0.452;%UPS桿質(zhì)心到運動副中心的距離
Ixx=0.93202;??Iyy=0.67346;?Izz=0.68159;???%動平臺的質(zhì)量的各軸慣性矩??(和柔性慣性量有點差別)
r1=0.71707;%定平臺的轉動副R1在Y軸正方向的距離
r2=0.6450;?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
f=pi/4;
r3=0.202;??%U副
r4=0.202;%?動平臺半徑
%?d=0.06711;%虎克鉸與YOZ平面的距離
g=3*pi/10;
h=2*pi/5;
alpha=0;
beta=0;
gamma=pi/2;

alpha1=0;beta1=0;gamma1=0;%對歐拉角求一階導數(shù)
alpha11=0;beta11=0;gamma11=0;%對歐拉角求二階導數(shù)

%?TT1(end+1)=t
%?
%?save?TT1?TT1

AXBO=1.150+0.03*sin(2*ti);%動系坐標原點在靜坐標系下的坐標賦值
AYBO=-0.03+0.03*cos(2*ti);
AZBO=0;
AXBO1=0.03*2*cos(2*ti);
AYBO1=-0.03*2*sin(2*ti);
AZBO1=0;
AXBO11=-0.03*2*2*sin(2*ti);
AYBO11=-0.03*2*2*cos(2*ti);
AZBO11=0;


Rb2=0.015;
RS2=Rb2+c2;
n=1.5;
ce=0.9;%恢復系數(shù)
ud=0.15;%摩擦因數(shù)
V0=0.0001;%給定的速度誤差
V1=0.5;

qk1=[AXBO1?AYBO1?AZBO1?alpha1?beta1?gamma1]‘;
qk2=[AXBO11?AYBO11?AZBO11?alpha11?beta11?gamma11]‘;?
APBO=[AXBO?AYBO?AZBO]‘;%
AVBO=[AXBO1?AYBO1?AZBO1]‘;
APBOjx=[x(1)?x(3)?x(5)]‘;
AVBOjx=[x(2)?x(4)?x(6)]‘;
qk1jx=[x(2)?x(4)?x(6)?x(8)?x(10)?x(12)]‘;
p11=[0?r1?0]‘;??????????????????????????%定平臺虎克鉸在定系下坐標
p12=[0?r2*cos(f)?r2*sin(f)]‘;
p13=[0?r2*cos(3*f)?r2*sin(3*f)]‘;
p14=[0?r2*cos(5*f)?r2*sin(5*f)]‘;
p15=[0?r2*cos(7*f)?r2*sin(7*f)]‘;

p21=[0?0?-r3]‘;?????????????????????????%動平臺球鉸在動系下坐標
p22=[0?r4*sin(h)?-r4*cos(h)]‘;
p23=[0?r4*cos(g)?r4*sin(g)]‘;
p24=[0?-r4*cos(g)?r4*sin(g)]‘;
p25=[0?-r4*sin(h)?-r4*cos(h)]‘;

ABR=[cos(alpha)*cos(beta)?cos(alpha)*sin(beta)*sin(gamma)-sin(alpha)*cos(gamma)?cos(alpha)*sin(beta)*cos(gamma)+sin(alpha)*sin(gamma);?sin(alpha)*cos(beta)?sin(alpha)*sin(beta)*sin(gamma)+cos(alpha)*cos(gamma)?sin(alpha)*sin(beta)*cos(gamma)-cos(alpha)*sin(gamma);-sin(beta)?cos(beta)*sin(gamma)?cos(beta)*cos(gamma)];%歐拉轉換矩陣



ABR1=[-sin(alpha)*cos(beta)*alpha1-cos(alpha)*sin(beta)*beta1(-sin(alpha)*sin(beta)*sin(gamma)-cos(alpha)*cos(gamma))*alpha1+cos(alpha)*cos(beta)*sin(gamma)*beta1+(cos(alpha)*sin(beta)*cos(gamma)+sin(alpha)*sin(gamma))*gamma1(-sin(alpha)*sin(beta)*cos(gamma)+cos(alpha)*sin(gamma))*alpha1+cos(alpha)*cos(beta)*cos(gamma)*beta1+(-cos(alpha)*sin(beta)*sin(gamma)+sin(alpha)*cos(gamma))*gamma1;
????cos(alpha)*cos(beta)*alpha1-sin(alpha)*sin(beta)*beta1(cos(alpha)*sin(beta)*sin(gamma)-sin(alpha)*cos(gamma))*alpha1+sin(alpha)*cos(beta)*sin(gamma)*beta1+(sin(alpha)*sin(beta)*cos(gamma)-cos(alpha)*sin(gamma))*gamma1(cos(alpha)*sin(beta)*cos(gamma)+sin(alpha)*sin(gamma))*alpha1+sin(alpha)*cos(beta)*

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