%%?從零基礎實現meanshift算法
close?all;
clear?all;
clc;

%%?根據一幅目標全可見的圖像圈定跟蹤目標
I=imread（‘0001.jpg‘）;
figure（1）;
imshow（I）;

[target_image	rect]???????????????=?imcrop（I）;????????????%?（rect（1）rect（2））為目標圖像左上角坐標????????????????????????????????????????????????????????????
%??————→?x軸?（1到544）?對應圖像的列?????????????????????%?rect（3）是目標圖像的寬度（x軸）????????????????
%?|?????????????????????????????????????????????????????????%?rect（4）是目標圖像的高度（y軸）?
%?|?????????????????????????????????????????????????????????%?目標圖像右下角坐標（rect（1）+rect（3），rect（3）+rect（4））
%?↓
%?y軸（1到960）?對應圖像的行

[target_rowtarget_coltarget_dim]??=?size（target_image）;???%?獲取目標圖像行數?列數?維度

%%?計算目標圖像的權值矩陣
target_center_x	=?rect（1）?+?rect（3）/2;??????????????????????%?目標圖像在原圖像中的?X軸中心坐標??????
target_center_y	=?rect（2）?+?rect（4）/2;??????????????????????%?目標圖像在原圖像中的?Y軸中心坐標

y（1）????????????=?target_row/2;?????????????????????????????%?目標圖像在目標圖像的?Y軸中心坐標??????
y（2）????????????=?target_col/2;?????????????????????????????%?目標圖像在目標圖像的?X軸中心坐標?
h???????????????=?（target_row/2）^2?+?（target_col/2）^2;??????%?帶寬?（對角線長度/2）^2
weight??????????=?zeros（target_rowtarget_col）;?????????????%?權值矩陣

for?i=1:target_row
????for?j=1:target_col
????????distance=（i-y（1））^2+（j-y（2））^2;?????????????????????%?計算每個點到中心坐標的距離
????????weight（ij）=1-distance/h;???????????????????????????%?Epanechnikov?profile（距離越大，權值越小）
????end
end

C???????????????=?1?/?sum（sum（weight））;?????????????????????%?歸一化系數?（?Tips?二維數組的求和?sum（sum（array））?）

%%?計算目標權值直方圖qu
TargetHistogram?????=?zeros（14096）;??????????????????????%?目標的權值直方圖
for?i=1:target_row
????for?j=1:target_col
????????%?rgb顏色空間量化為16*16*16?bins
????????%?rgb的三個維度每一維都0~255?除16之后?每一維就降到了0~15
????????q_r?????=?fix（double（target_image（ij1））/16）;??????%?fix為?下取整函數
????????q_g?????=?fix（double（target_image（ij2））/16）;
????????q_b?????=?fix（double（target_image（ij3））/16）;
????????q_temp	=?q_r*256?+?q_g*16?+?q_b;???????????????????%?降維之后的16位的RGB空間可以把顏色分為?16*16*16=4096種顏色
????????????????????????????????????????????????????????????%?這里是計算目標圖像的每一個像素點的顏色在直方圖的坐標
????????%?計算得到坐標是0~4095，因此數組系數要＋1
????????TargetHistogram（q_temp+1）=?TargetHistogram（q_temp+1）+weight（ij）;????????
????????????????????????????????????????????????????????????%?統計目標的特征直方圖中每一種顏色的權重
????????????????????????????????????????????????????????????%?目標圖像每一個像素點都會對應直方圖中一種顏色
????????????????????????????????????????????????????????????%?之前根據距離目標中心的距離也計算了每個像素點的權重的
????end
end
TargetHistogram?=?TargetHistogram*C;??
rect（3）=ceil（rect（3））;	%?rect（3）是目標圖像的寬度?ceil是上取整
rect（4）=ceil（rect（4））;??%?rect（4）是目標圖像的高度

bar（TargetHistogram0.5）;
title（‘目標特征直方圖‘）;
?
%%?讀取序列圖像開始跟蹤
ImageSequence	=?dir（‘*.jpg‘）;
SequenceLength	=?length（ImageSequence）;

%?%?驗證序列順序是否正常
%?for?l=1:SequenceLength
%???????ImageSequence（l）.name
%?end

IterationMaxNum?=?2;
for?l=1:SequenceLength
	CurrentImage	=?imread（ImageSequence（l）.name）;????
????IterationNum	=?0;
????Y???????????????=?[22];
????while（?（Y（1

?屬性????????????大小?????日期????時間???名稱
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