function?Aorar1=orar1（Atmn）
i=1;
for?j=1:n
????a（j）=0;
????a（j）=sum（A（:j））;
????a（j）=a（j）/m;
????if（a（j）>=t）
????????Aorar1（i）=j;
????????support1（i）=a（i）;
????????save?support1?support1;
????????i=i+1;
????end
end
%------------------------------------------------------------產(chǎn)生1大項(xiàng)集
if（i==1）
????Aorar1=0;
end

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件?????894976??2014-05-11?20:08??數(shù)據(jù)挖掘\原始題目\附件.xls

?????文件?????149048??2014-05-11?20:10??數(shù)據(jù)挖掘\原始題目\題目.pdf

?????文件?????825856??2007-01-08?10:24??數(shù)據(jù)挖掘\程序與數(shù)據(jù)\data.xls

?????文件????????738??2007-01-08?10:07??數(shù)據(jù)挖掘\程序與數(shù)據(jù)\dataA.mat

?????文件????????334??2014-05-03?15:54??數(shù)據(jù)挖掘\程序與數(shù)據(jù)\orar1.m

?????文件????????461??2014-05-03?15:42??數(shù)據(jù)挖掘\程序與數(shù)據(jù)\orar2.m

?????文件???????2330??2014-05-03?15:50??數(shù)據(jù)挖掘\程序與數(shù)據(jù)\orark.m

?????文件????????254??2007-01-08?10:47??數(shù)據(jù)挖掘\程序與數(shù)據(jù)\test2.m

?????文件??????85780??2018-06-14?11:36??數(shù)據(jù)挖掘\論文.docx

?????目錄??????????0??2018-06-14?11:38??數(shù)據(jù)挖掘\原始題目

?????目錄??????????0??2018-06-14?11:39??數(shù)據(jù)挖掘\程序與數(shù)據(jù)

?????目錄??????????0??2018-06-14?11:41??數(shù)據(jù)挖掘

-----------?---------??----------?-----??----

??????????????1959777????????????????????12