function?[GcKpTiTd]=bestd（PIDvars）
%參數(shù)PID是校正器的類(lèi)型，當(dāng)PID=1時(shí)，為計(jì)算P調(diào)節(jié)器的參數(shù)；當(dāng)PID=2時(shí)，為計(jì)算PI調(diào)節(jié)器的參數(shù)；當(dāng)PID=3時(shí)，為計(jì)算PID調(diào)節(jié)器的參數(shù)
%參數(shù)vars為帶延遲一慣性環(huán)節(jié)模型的K、T、tau，已知這三參數(shù)為：K=vars（1）；T=vars（2）；tau=vars（3）
%參數(shù)Gc為校正器傳遞函數(shù)
%參數(shù)Kp為校正器的比例系數(shù)
%參數(shù)Ti為校正器的積分時(shí)間常數(shù)
%參數(shù)Td為校正器的微分時(shí)間常數(shù)
K=vars（1）;T=vars（2）;
tau=vars（3）;Ic=vars（4）;
Kp=[];Ti=[];Td=[];
if?PID==1
????ABtab=[0.902?1.414?0.904;-0.985?-0.917?-1.084];
elseif?PID==2
????ABtab=[0.984?1.305?0.859;-0.986?-0.959?-0.977;...
????????0.608?0.492?0.674;-0.707?-0.739?-0.680];
elseif?PID==3
????ABtab=[1.435?1.495?1.357;-0.921?-0.945?-0.947;...
????????0.878?1.101?0.842;-0.749?-0.771?-0.738;...
????????0.482?0.560?0.381;1.137?1.006?0.995];
end
ii=0;
tt=tau/T;
if?PID==1
????a1=ABtab（1ii+Ic）;
????b1=ABtab（2ii+Ic）;
????Kp=（a1*（tt^b1））/K;
elseif?PID==2
????a1=ABtab（1ii+Ic）;
????b1=ABtab（2ii+Ic）;
????a2=ABtab（3ii+Ic）;
????b2=ABtab（4ii+Ic）;
????Kp=（a1*（tt^b1））/K;
????Ti=T/（a2*（tt^b2））;
elseif?PID==3
????a1=ABtab（1ii+Ic）;
????b1=ABtab（2ii+Ic）;
????a2=ABtab（3ii+Ic）;
????b2=ABtab（4ii+Ic）;
????a3=ABtab（5ii+Ic）;
????b3=ABtab（6ii+Ic）;
????Kp=（a1*（tt^b1））/K;
????Ti=T/（a2*（tt^b2））;
????Td=T*a3*（tt^b3）;
end
if?PID==1
????Gc=Kp;
elseif?PID==2
????nn=[Kp*Ti?Kp];
????dd=[Ti?0];
????Gc=tf（nndd）;
elseif?PID==3
????nn=[Kp*Ti*Td?Kp*Ti?Kp];
????dd=[Ti?0];
????Gc=tf（nndd）;
end

?屬性????????????大小?????日期????時(shí)間???名稱(chēng)
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?????文件???????1472??2016-11-05?11:42??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\bestd.m

?????文件????????345??2016-11-05?08:49??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\cqiz_root.m

?????文件????????394??2016-11-05?11:26??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\cqjz_freq.m

?????文件????????354??2016-11-05?11:31??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\cqzh_dfreq.m

?????文件????????354??2016-11-05?11:30??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\cqzh_freq.m

?????文件???????1065??2016-11-05?11:40??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\jz_C_C.m

?????文件????????839??2016-11-05?09:19??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\jz_PID.m

?????文件????????689??2016-11-05?11:39??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\kttau.m

?????文件????????119??2016-11-05?09:23??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_1.m

?????文件????????346??2016-11-05?09:42??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_2.m

?????文件????????170??2016-11-05?09:42??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_3.m

?????文件????????237??2016-11-05?09:43??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_4.m

?????文件????????197??2016-11-05?09:43??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_5.m

?????文件????????191??2016-11-05?09:44??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_6.m

?????文件????????188??2016-11-05?09:45??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_7.m

?????文件????????401??2016-11-05?09:45??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li10_8.m

?????文件????????229??2016-11-05?09:51??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li11_1.m

?????文件????????340??2016-11-05?09:53??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li11_4.m

?????文件????????289??2016-11-05?09:55??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li12_11.m

?????文件????????133??2016-11-05?09:56??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li13_1.m

?????文件????????236??2016-11-05?09:56??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li13_2.m

?????文件????????347??2016-11-05?09:57??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li13_3.m

?????文件????????320??2016-11-05?09:58??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li13_4.m

?????文件????????178??2016-11-05?09:59??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_2.m

?????文件????????352??2016-11-05?10:00??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_3.m

?????文件????????246??2016-11-05?10:01??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_5.m

?????文件????????218??2016-11-05?10:02??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_6.m

?????文件????????583??2016-11-05?10:03??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_6_.m

?????文件????????164??2016-11-05?10:03??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_7.m

?????文件????????261??2016-11-05?10:03??494966源碼-MATLAB?R2016a?控制系統(tǒng)設(shè)計(jì)與仿真35個(gè)案例分析\li14_8.m

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