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  • 大小: 1.05MB
    文件類型: .rar
    金幣: 2
    下載: 1 次
    發(fā)布日期: 2021-06-21
  • 語言: Matlab
  • 標(biāo)簽: 通信仿真??

資源簡介

是FM調(diào)頻立體聲的調(diào)制解調(diào)的matlab仿真代碼，實(shí)現(xiàn)了對雙聲道語音的調(diào)制和解調(diào)，非simulink方式，完完全全的matlab代碼 This is for FM stereo radio signal modulation and de-modulation code. it is not for matlab simulink, it is completely matlab code, you can follow it and for understanding FM stereo signal generate very well.

資源截圖

代碼片段和文件信息 

%?clc;
%?clear;
%?close?all;
function?Demodulation（s_toutput_file）

%%%%%%%%%%%%%%%%%%%%%%%%%??sample?rate??%%%%%%%%%%%%%%%%%%%%%%%%%
ExtensionFactor=3;??????????????????????????%?raise?sample?rate?3?times
FS=44100;???????????????????????????????????%?sample?rate?of?wave?file
fs=FS*ExtensionFactor;??????????????????????%?sampling?rate
ts=1/fs;

%%%%%%%%%%%%%%%%%%??receive?the?signal:?s_t??%%%%%%%%%%%%%%%%%%%%
%?load?s_t_matlab;????????????????????????????%?s_t:?input?from?data-file
[tmpN]=size（s_t）;??????????????????????????%?points?of?samples
MusicLen=N/ExtensionFactor;?????????????????
t=-N/2*ts:ts:（N/2-1）*ts;

%%%%%%%%%%%%%%%%%%??Obtain?s1_t?and?s2_t?from?s_t?%%%%%%%%%%%%%%%
%通過頻譜圖確定濾波器的大致帶寬值B
Nfft=2^ceil（log2（N）+2）;
df=fs/Nfft;fk=（-Nfft/2:Nfft/2-1）*df;
s_f=ts*fft

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????2301??2017-03-02?15:35??FM?stereo?signal?modulation?and?demodulation?matlab?code\Demodulation.m

?????文件?????138283??2017-03-02?16:02??FM?stereo?signal?modulation?and?demodulation?matlab?code\FM調(diào)制解調(diào)立體聲.docx

?????文件????????728??2017-03-02?15:33??FM?stereo?signal?modulation?and?demodulation?matlab?code\Modulation.m

?????文件????1769516??2017-03-01?16:59??FM?stereo?signal?modulation?and?demodulation?matlab?code\speech.wav

?????文件????????220??2017-03-02?15:34??FM?stereo?signal?modulation?and?demodulation?matlab?code\TotalRun.m

?????目錄??????????0??2017-03-02?16:02??FM?stereo?signal?modulation?and?demodulation?matlab?code

-----------?---------??----------?-----??----

??????????????1911048????????????????????6


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