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    文件類型: .rar
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    發(fā)布日期: 2021-06-12
  • 語言: Matlab
  • 標(biāo)簽: 勢(shì)函數(shù)??

資源簡(jiǎn)介

勢(shì)函數(shù)的matlab實(shí)現(xiàn)

資源截圖

代碼片段和文件信息

clc
clear?all

start?=?[00;
?????????????01;
?????????????10;
?????????????11];
w?=?[1122];
Nc?=?0;
r?=?[];?
G?=?0;?
k?=?1;
N?=?4;?
m?=?1;?
n?=?0;
while(Nc?????r(1)?=?0;
????if?(?w(m)?==?1)?%屬于第一類
????????if?(G?>?0)
????????????Nc?=?Nc?+?1;
????????????r(k+1)?=?0;
????????end
????????if?(?G?<=?0)
????????????r?(?k+1?)?=?1;
????????????Nc?=?0;
????????end
????end
????if?(w(m)?==?2)
????????if?(G?????????????r(k+1)?=?0;
????????????Nc?=?Nc?+?1;
????????end
????????if?(?G?>=?0)
????????????r(k+1)?=?-1;
????????????Nc?=?0;
????????end
????end
????k?=?k+1;
????m?=?mod(k-1N)?+?1;
????G?=?0;
????for?i=1:k
????????n?=?mod(i-1N)?+?1;
????????G?=?G?+?r(i)*KA(?start(m?1)start(n1)?start(m2)start(n2)?);
????end
end
X?=?input(‘please?input?X:‘)
G?=?0;
k?=?k-1;
for?i?=?1:k
????n?=?mod(i-1N)?+?1;
????G?=?G?+?r(i)*KA(X(1)start(n1)X(2)start(n2)?);
end
if?(G?>?0)
????fprintf(‘X?is?first?kind\n‘);
else
????fprintf(‘X?is?secont?kind\n‘);
end


????????
????????
????????
????????
????????
????????

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----

?????文件???????1092??2016-03-23?22:45??勢(shì)函數(shù)\demoka.m

?????文件?????????68??2016-03-23?22:35??勢(shì)函數(shù)\KA.m

?????目錄??????????0??2016-03-23?22:35??勢(shì)函數(shù)

-----------?---------??----------?-----??----

?????????????????1160????????????????????3


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