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    發(fā)布日期: 2021-06-11
  • 語(yǔ)言: Matlab
  • 標(biāo)簽: Jakes仿真??

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Jakes模型matlab仿真,在另外一個(gè)網(wǎng)站下載下來(lái),進(jìn)行LTE-A無(wú)限信道部分仿真,仿真程序沒(méi)有問(wèn)題,和大家分享

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%?Simulation?Of?Jakes?Model?
clear?all;?
f_max?=?10;?
M?=?9;?????????????????????????????????%?#?of?low?frequency?oscillators?-?1?
N?=?4*M+2;?
Ts=1e-03;?
sq?=?2/sqrt(N);?
sigma?=?1/sqrt(2);?
theta?=?0;??????????????????????????????%?Fixed?Phase?
count?=?0;?
t0=0.24;?%(0.24?0.45);?
????for?t?=?0:Ts:3????????????%?Varying?time?
???????????????
????????count?=?count?+?1?
????????g(count)?=?0;?
????????for?n?=?1?:?M+1?
????????????if?n?==?M?
???????????????c_q(countn)?=?2*sigma*sin(pi*n/M);??%?Gain?associated?with?quadrature?component?
???????????????c_i(countn)?=?2*sigma*cos(pi*n/M);??%?Gain?associated?with?inphase?component?
???????????????f_i(countn)?=?f_max*cos(2*pi*n/N);??%?Discrete?doppler?frequencies?of?inphase?component?
???????????????f_q(countn)?=?f_max*cos(2*pi*n/N);??%?Discrete?doppler?frequencies?of?quadrature?component?
???????????else?
???????????????c_i(countn)?=?sqrt(2)*cos(pi/4);?
???????????????c_q(countn)?=?sqrt(2)*sin(pi/4);?
???????????????f_i(countn)?=?f_max;?
???????????????f_q(countn)?=?f_max;?
???????????end;??%?end?if?
????????????????
???????????????g_i(countn)?=??c_i(countn)*cos(2*pi*f_i(countn)*(t-t0)?+?theta);?%?Inphase?component?for?one?oscillator?
??????????????
???????????????g_q(countn)?=??c_q(countn)*cos(2*pi*f_q(countn)*(t-t0)?+?theta);?%?Quadrature?component?for?one?oscillator?
????????????????
???????end;???%end?n?
???????tp(count)?=??sq*sum(g_i(count1:M+1));%?Total?Inphase?component??
???????tp1(count)?=?sq*sum(g_q(count1:M+1));%?Total?quadrature?component??
???????
???end;??%?end?count?no?n?again?
???envelope=sqrt(tp.^2+tp1.^2);?
???rmsenv=sqrt(sum(envelope.^2)/count);?
????
???[auto_ilag_i]?=?xcorr(tp‘coeff‘)?;???%?Auto-correlation?associated?with?inphase?component?

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