function?lic?=?actxlicense（progid）

if?strcmpi（progid?‘a(chǎn)ir.airctrl.1‘）
lic?=?‘Copyright?（c）?1996?‘;
return;
end

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2013-01-07?15:42??基于matlab的信號(hào)采樣與恢復(fù)\
?????文件?????????671??2012-12-30?01:23??基于matlab的信號(hào)采樣與恢復(fù)\Gibbs.m
?????文件?????????113??2012-12-25?19:07??基于matlab的信號(hào)采樣與恢復(fù)\actxlicense.m
?????文件????????9478??2012-12-19?19:26??基于matlab的信號(hào)采樣與恢復(fù)\gui.fig
?????文件????????6686??2012-12-19?19:27??基于matlab的信號(hào)采樣與恢復(fù)\gui.m
?????文件????????9600??2012-12-19?20:33??基于matlab的信號(hào)采樣與恢復(fù)\gui2.fig
?????文件????????6754??2012-12-25?19:27??基于matlab的信號(hào)采樣與恢復(fù)\gui2.m
?????文件?????????757??2012-12-19?21:06??基于matlab的信號(hào)采樣與恢復(fù)\matlab_5_2.m
?????目錄???????????0??2013-01-07?15:42??基于matlab的信號(hào)采樣與恢復(fù)\sample\
?????文件???????29869??2012-12-26?19:20??基于matlab的信號(hào)采樣與恢復(fù)\sample\sample.mdl
?????文件?????????632??2012-12-26?18:48??基于matlab的信號(hào)采樣與恢復(fù)\sample\signal_pinpu.m
?????文件????????6777??2012-12-26?19:00??基于matlab的信號(hào)采樣與恢復(fù)\sample\一階濾波后的波形.fig
?????文件????????6351??2012-12-26?18:59??基于matlab的信號(hào)采樣與恢復(fù)\sample\信號(hào)源波形.fig
?????文件???????29751??2012-12-25?20:46??基于matlab的信號(hào)采樣與恢復(fù)\sample.mdl
?????文件????????8025??2012-12-25?18:43??基于matlab的信號(hào)采樣與恢復(fù)\shiyan2.fig
?????文件????????3710??2012-12-25?19:32??基于matlab的信號(hào)采樣與恢復(fù)\shiyan2.m
?????文件????????1374??2012-12-30?00:56??基于matlab的信號(hào)采樣與恢復(fù)\square.m