資源簡(jiǎn)介
基于MEMS傳感器的步態(tài)檢測(cè)代碼,用matlab仿真實(shí)現(xiàn),大家可以參考!

代碼片段和文件信息
function?c1?=?Byte_merging(?c?)
%UNtitleD3?此處顯示有關(guān)此函數(shù)的摘要
%???此處顯示詳細(xì)說(shuō)明
%%?字節(jié)合并
line?=?length(c);
c1?=?zeros(line14);
for?i?=1:line
%?????c1(i1)=c(i1)*256+c(i2);
%?????c1(i2)=c(i3)*256+c(i4);
????c1(i1)=c(i1);
????c1(i2)=c(i2);
????c1(i3)=c(i3);
????c1(i4)=c(i4);
????%四元數(shù)
????c1(i5)=c(i5)*256+c(i6);
????c1(i6)=c(i7)*256+c(i8);
????c1(i7)=c(i9)*256+c(i10);
????c1(i8)=c(i11)*256+c(i12);
????%加速度
????c1(i9)=c(i13)*256+c(i14);
????c1(i10)=c(i15)*256+c(i16);
????c1(i11)=c(i17)*256+c(i18);
????%角速度
????c1(i12)=c(i19)*256+c(i20);
????c1(i13)=c(i21)*256+c(i22);
????c1(i14)=c(i23)*256+c(i24);
end
end
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2017-05-12?12:28??bin\
?????目錄???????????0??2017-05-12?12:28??bin\bin\
?????目錄???????????0??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\
?????目錄???????????0??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\函數(shù)\
?????目錄???????????0??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\函數(shù)\步態(tài)檢測(cè)\
?????文件?????????706??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\函數(shù)\步態(tài)檢測(cè)\Byte_merging.m
?????文件???????15087??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\函數(shù)\步態(tài)檢測(cè)\Gait_Detection.m
?????文件?????????605??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\函數(shù)\步態(tài)檢測(cè)\peak.m
?????文件?????????924??2017-05-12?12:28??bin\bin\MATLAB學(xué)習(xí)\函數(shù)\步態(tài)檢測(cè)\uint2int.m
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