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    文件類型: .m
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    發(fā)布日期: 2021-05-14
  • 語(yǔ)言: Matlab
  • 標(biāo)簽: matlab??m文件??

資源簡(jiǎn)介

基于相差干涉儀算法的信號(hào)DOA,matlab仿真

資源截圖

代碼片段和文件信息

clc;
clear;

%?讀入數(shù)據(jù)
fid1?=?fopen(‘s.bin‘?‘rb‘);
fid2?=?fopen(‘c.bin‘?‘rb‘);

temps?=?fread(fid1?‘int32‘);
tempc?=?fread(fid2?‘int32‘);

%?組織數(shù)據(jù)
channelNO?=?5;
signalLen?=?512;
signalTemp?=?zeros(channelNO?signalLen?*?2);
correctTemp?=?zeros(channelNO?signalLen?*?2);
signalI?=?zeros(channelNO?signalLen);
signalQ?=?zeros(channelNO?signalLen);
correctI?=?zeros(channelNO?signalLen);
correctQ?=?zeros(channelNO?signalLen);

for?z?=?1?:?floor(length(temps)?/?channelNO?/?signalLen?/?2)?-?1;
????for?i?=?1?:?channelNO;
????????signalTemp(i?:)?=?temps((i?-?1)?*?signalLen?*?2?+?1?+?z?*?channelNO?*?signalLen?*?2?...
????????????:?i?*?signalLen?*?2??+?z?*?channelNO?*?signalLen?*?2);
????????correctTemp(i?:)?=?tempc((i?-?1)?*?signalLen?*?2?+?1??+?z?*?channelNO?*?signalLen?*?2?...
????????????:?i?*?signalLen?*?2??+?z?*?channelNO?*?signalLen?*?2);
????end

????for?i?=?1?:?channelNO;
????????for?j?=?1?:?signalLen;
????????????signalI(i?j)?=?signalTemp(i?2?*?j?-?1);
????????????signalQ(i?j)?=?signalTemp(i?2?*?j);
????????????correctI(i?j)?=?correctTemp(i?2?*?j?-?1);
????????????correctQ(i?j)?=?correctTemp(i?2?*?j);
????????end
????end

%?校正信號(hào)坐標(biāo)旋轉(zhuǎn)并平均
????for?i?=?2?:?channelNO;
????????Ic(i)?=?mean(correctI(i?-?1?:)?.*?correctI(i?:)?+?correctQ(i?-?1?:)?.*?correctQ(i?:));
????????Qc(i)?=?mean(correctI(i?-?1?:)?.*?correctQ(i?:)?-?correctI(i?:)?.*?correctQ(i?-?1?:));
????end

%?求出校正相位差
????vc?

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