資源簡介
不用任何jar包,解析xml內容。相同節點多個時。可以一次解析所有的內容。
代碼片段和文件信息
package?cn.com.wdc.sun.xml;
public?class?Test?{
public?static?void?main(String[]?args)?{
try?{
String?xmldoc?=?““+
???? “ “+
???? “ “+
???? “ “+
???? “ “+
???? “ “;
/**
?*第三個參數為獲取第幾個節點里的內容
?*如果為0或大于節點數,就會取出所有
?*/
String?sb?=?xmlNode(xmldoc“EdorDetail“0);
/**
?*取出的內容以“”分割。
?*/
System.out.println(sb.replaceAll(““?“\r\n“));
}?catch?(Exception?e)?{
e.printStackTrace();
}
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????314??2013-05-24?11:45??xm
?????文件?????????66??2013-05-24?11:46??xm
?????文件????????379??2013-04-01?11:26??xm
?????文件???????1743??2013-05-24?11:43??xm
?????文件???????3366??2013-05-24?11:42??xm
?????目錄??????????0??2013-05-24?11:34??xm
?????目錄??????????0??2013-05-24?11:34??xm
?????目錄??????????0??2013-05-24?11:34??xm
?????目錄??????????0??2013-05-24?11:34??xm
?????目錄??????????0??2013-05-24?11:34??xm
?????目錄??????????0??2013-05-24?11:34??xm
-----------?---------??----------?-----??----
?????????????????5868????????????????????11
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