package?五子棋人機(jī)版;

public?class?assume?{//假設(shè)人下的下一步并從預(yù)知的下一步中找到最優(yōu)解
	static?point?p;
	public?static?boolean?checkfour（boolean[][]?bboolean[][]?h）?{
		//創(chuàng)建操作副本防止影響數(shù)據(jù)源
		boolean?b1[][]=new?boolean[b.length][h.length];
		boolean?h1[][]=new?boolean[b.length][h.length];
		for?（int?i?=?0;?i?			for?（int?j?=?0;?j?				b1[i][j]=b[i][j];
				h1[i][j]=h[i][j];
				
			}
			
		}
		
		
		for?（int?i?=?0;?i?			for?（int?j?=?0;?j?				if?（b1[i][j]||h1[i][j]）?{
					
				}
				else?{
					h1[i][j]=true;//假定該點(diǎn)為真
					double?numd[][]=statenum.getstatenum（h1b1）;//計(jì)算當(dāng)前非人機(jī)的權(quán)值
					for?（int?i1?=?0;?i1?						for?（int?j1?=?0;?j1?							if?（numd[i1][j1]>=1.0）?{
								System.out.println（“如果“+i+““+j+“為真則“+i1+““+j1+“權(quán)重為“+numd[i1][j1]）;
							}
							
							if?（numd[i1][j1]>=4.0）?{
								System.err.println（“出現(xiàn)必爭點(diǎn)“+i+“\t“+j）;
								p=new?point（ij）;
						????return?true;
							}
							
						}
					
						
					}h1[i][j]=false;
				}
				
			}
			
		}
		
		return?false;
	}

}

?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2018-09-26?16:16??五子棋\
?????目錄???????????0??2018-09-26?16:16??五子棋\src\
?????目錄???????????0??2018-09-26?16:16??五子棋\src\五子棋人機(jī)版\
?????文件????????1206??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\assume.java
?????文件?????????256??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\checkisright.java
?????文件????????8127??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\checkwin.java
?????文件????????8205??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\checkwinforassume.java
?????文件????????1321??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\compulterpeople.java
?????文件???????11325??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\fiveinarow.java
?????文件?????????360??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\point.java
?????文件????????3183??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\starter.java
?????文件?????????459??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\statenum.java
?????文件????????1080??2018-08-26?08:26??五子棋\src\五子棋人機(jī)版\store.java